Dielectric and base contributions to one-dimensional thermal resistanceExample: the dielectric dominates the base-only change100 mm² area · 100 µm / 2 W/m·K dielectric · 1.5 mm base · 0.20 K/W interfaceIllustrative base conductivities: aluminum 200; copper 390 W/m·KAluminumCopper0.775 K/W0.738 K/WDielectric 0.500Base 0.075TIM 0.200Dielectric 0.500Base 0.038TIM 0.200At 10 W: about 0.37 K less temperature rise across this pathThis model does not predict lateral heat spreading or a product junction temperature.Change dielectric thickness, heat-flow area and mounting conditions in the calculator.Metal thermal conductivity (W/m·K) and board thermal resistance (K/W) are different quantities.